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प्रश्न
Solve the given inequality for real x: 37 – (3x + 5) ≥ 9x – 8(x – 3)
उत्तर
The given inequality,
37 – (3x + 5) ≥ 9x – 8(x – 3)
37 – 3x - 5 ≥ 9x – 8x + 24
– 3x + 32 ≥ x + 24
32 - 24 ≥ x + 3x
8 ≥ 4x
= 2 ≥ x
Thus, all real numbers x, which are less than or equal to 2, are the solutions of the given inequality.
Hence, the solution set of the given inequality is (–∞, 2].
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