Advertisements
Advertisements
प्रश्न
Solve the inequation:
3x + 1 ≥ 6x – 4
उत्तर
3x + 1 ≥ 6x – 4
Subtracting 3x from both sides, we get
1 ≥ 3x – 4
Adding 4 on both sides, we get
5 ≥ 3x
Dividing by 3 on both sides, we get
`5/3` ≥ x
i.e., `"x" ≤ 5/3`
i.e., x takes all real values less than or equal to `5/3`.
∴ the solution set is `[-∞,5/3]`
APPEARS IN
संबंधित प्रश्न
Solve the following inequation: 3x – 36 > 0
Solve the following inequation:
7x – 25 ≤ – 4
Solve the following inequation: `0 < ("x" - 5)/4 < 3`
Solve the following inequation: |7x – 4| < 10
Solve the inequation:
4 – 2x < 3(3 – x)
Solve the inequation:
`3/4 "x" - 6 ≤ "x" - 7`
Solve the inequation:
– 8 ≤ – (3x – 5) < 13
Solve the inequation:
2|4 – 5x| ≥ 9
To receive Grade ‘A’ in a course, one must obtain an average of 90 marks or more in five examinations (each of 100 marks). If Sunita’s marks in first four examinations are 87, 92, 94, and 95, find minimum marks that Sunita must obtain in fifth examination to get grade ‘A’ in the course.
The region represented by {z = x + iy ∈ C : |z| – Re(z) ≤ 1} is also given by the inequality is ______.
Consider the two sets : A = {m ∈ R : both the roots of x2 – (m + 1)x + m + 4 = 0 are real} and B = [–3, 5). Which of the following is not true?
Let S be the set of all real roots of the equation, 3x(3x – 1) + 2 = |3x – 1| + |3x – 2|. Then S ______.
All the-pairs (x, y) that satisfy the inequality `2^sqrt(sin^2x - 2sinx + 5), 1/(4^(sin^2y)) ≤ 1` also satisfy the equation ______.
