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Question
Solve the inequation:
3x + 1 ≥ 6x – 4
Solution
3x + 1 ≥ 6x – 4
Subtracting 3x from both sides, we get
1 ≥ 3x – 4
Adding 4 on both sides, we get
5 ≥ 3x
Dividing by 3 on both sides, we get
`5/3` ≥ x
i.e., `"x" ≤ 5/3`
i.e., x takes all real values less than or equal to `5/3`.
∴ the solution set is `[-∞,5/3]`
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