Advertisements
Advertisements
प्रश्न
Solve the numerical problem.
Height of a TV tower is 600 m at a given place. Calculate its coverage range if the radius of the Earth is 6400 km. What should be the height to get the double coverage area?
उत्तर
Given: h = 600 m, R = 6.4 × 106 m
To find: Range (d)
Height to get the double coverage (h′)
Formula: d = `sqrt(2"hR")`
Calculation: From the formula,
d = `sqrt(2xx600xx6.4xx10^6)`
= 87.6 × 103
= 87.6 km
Now, for A′ = 2A
π(d′)2 = 2(πd2)
∴ (d′)2 = 2d2
From formula,
h′ = `(("d"^′)^2)/(2"R")`
= `(2"d"^2)/(2"R")`
= 2 × h ....`(∵ "h" = "d"^2/(2"R"))`
= 2 × 600
= 1200 m
The coverage range is 87.6 km and the height of antenna to double the area should be 1200 m.
APPEARS IN
संबंधित प्रश्न
Choose the correct option.
The maximum distance up to which TV transmission from a TV tower of height h can be received is proportional to
Choose the correct option.
If a TV telecast is to cover a radius of 640 km, what should be the height of the transmitting antenna?
Answer briefly.
What are EM waves?
Answer briefly.
How are EM waves produced?
Answer briefly.
How does the effective power radiated by an antenna vary with wavelength?
Answer briefly.
Why should broadcasting programs use different frequencies?
Solve the numerical problem.
In an EM wave, the electric field oscillates sinusoidally at a frequency of 2 × 1010 Hz. What is the wavelength of the wave?
Solve the numerical problem.
A TV tower has a height of 200 m. How much population is covered by TV transmission if the average population density around the tower is 1000/km2? (Radius of the Earth = 6.4 × 106 m)
