Advertisements
Advertisements
प्रश्न
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
उत्तर
We have, –ab – bc – ca – 2(ab + bc + ca) = –ab – bc – ca – 2ab – 2bc – 2ca
On combining the like terms,
= –ab – 2ab – bc – 2bc – ca – 2ca
= –3ab – 3bc – 3ca
APPEARS IN
संबंधित प्रश्न
Simplify: (x + y – z) + (3x – 5y + 7z) – (14x + 7y – 6z)
Subtract – 3ab – 8 from 3ab + 8. Also, subtract 3ab + 8 from – 3ab – 8
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
Subtract:
7p(3q + 7p) from 8p(2p – 7q)
The subtraction of 5 times of y from x is ______.
Subtract the following expressions:
x4 + 3x3y3 + 5y4 from 2x4 – x3y3 + 7y4
Subtract the following expressions:
–2a2 – 2b2 from –a2 – b2 + 2ab
Subtract the following expressions:
x3y2 + 3x2y2 – 7xy3 from x4 + y4 + 3x2y2 – xy3
How much is 21a3 – 17a2 less than 89a3 – 64a2 + 6a + 16?
To what expression must 99x3 – 33x2 – 13x – 41 be added to make the sum zero?
