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Question
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
Solution
We have, –ab – bc – ca – 2(ab + bc + ca) = –ab – bc – ca – 2ab – 2bc – 2ca
On combining the like terms,
= –ab – 2ab – bc – 2bc – ca – 2ca
= –3ab – 3bc – 3ca
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