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Maharashtra State BoardSSC (English Medium) 7th Standard

Subtract the second expression from the first. (6x2 + 7xy + 16y2); (16x2 − 17xy) - Marathi (Second Language) [मराठी (द्वितीय भाषा)]

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Question

Subtract the second expression from the first.

(6x2 + 7xy + 16y2); (16x2 − 17xy)

Sum

Solution

(6x2 + 7xy + 16y2 ) − (16x2 − 17xy)

= 6x2 + 7xy + 16y2 − 16x2 + 17xy

= (6x2 − 16x2) + (7xy + 17xy) + 16y2

= −10x2 + 24xy + 16y2

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Chapter 8: Algebraic Expressions and Operations on Them - Practice Set 34 [Page 58]

APPEARS IN

Balbharati Mathematics [English] 7 Standard Maharashtra State Board
Chapter 8 Algebraic Expressions and Operations on Them
Practice Set 34 | Q 1.4 | Page 58
Balbharati Integrated 7 Standard Part 2 [English Medium] Maharashtra State Board
Chapter 3.4 Algebraic Expressions and Operations on them
Practice Set 34 | Q (iv) | Page 71

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