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Tamil Nadu Board of Secondary EducationSSLC (English Medium) Class 8

Subtract: −2(xy)2 (y3 + 7x2y + 5) from 5y2 (x2y3 – 2x4y + 10x2) - Mathematics

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Question

Subtract: −2(xy)2 (y3 + 7x2y + 5) from 5y2 (x2y3 – 2x4y + 10x2)

Sum

Solution

5y2 (x2y3 − 2x4y + 10x2) − [(−2)(xy)2 (y3 + 7x2y + 5)]

= [5y2(x2y3) − 5y2(2x4y) + 5y2(10x2)] −[(−2)x2y2(y3 + 7x2y + 5)]

= (5y5x2 − 10x4y3 + 50x2y2) − [(−2x2y2)(y3) + (−2x2y2)(7x2y) + (−2x2y2)(5)]

= 5x2y5 − 10x4y3 + 50x2y2 −[−2x2y5 − 14x4y3 −10x2y2]

= 5x2y5 − 10x4y3 + 50x2y2 + 2x2y5 + 14x4y3 + 10x2y2

= (5 + 2)x2y5 + (−10 + 14)x4y3 + (50 + 10)x2y2

= 7x2y5 + 4x4y3 + 60x2y2

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Chapter 3: Algebra - Exercise 3.5 [Page 97]

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Samacheer Kalvi Mathematics [English] Class 8 TN Board
Chapter 3 Algebra
Exercise 3.5 | Q 1 | Page 97
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