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प्रश्न
Subtract the second expression from the first.
(14x2 + 8xy + 3y2); (26x2 − 8xy − 17y2)
उत्तर
(14x2 + 8xy + 3y2) − (26x2 − 8xy − 17y2)
= 14x2 + 8xy + 3y2 − 26x2 + 8xy + 17y2
= (14x2 − 26x2) + (8xy + 8xy) + (3y2 + 17y2)
= −12x2 + 16xy + 20y2
संबंधित प्रश्न
Subtract the second expression from the first.
(5x + 4y + 7z); (x + 2y + 3z)
Sum of a – b + c and – a + b – c is zero
Subtract: 4k from 12k
Subtract: 7xyz from 17xyz
Simplify: (x + y – z) + (3x – 5y + 7z) – (14x + 7y – 6z)
When we subtract ‘a’ from ‘−a’, we get __________
Subtract:
6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2
Subtract the following expressions:
11 – 15y2 from y3 – 15y2 – y – 11
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
(A + B) – C
Subtract the sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2 from the sum of ab + 2b2 and 3b2 – a2.
