Advertisements
Advertisements
प्रश्न
Subtract the second expression from the first.
(14x2 + 8xy + 3y2); (26x2 − 8xy − 17y2)
उत्तर
(14x2 + 8xy + 3y2) − (26x2 − 8xy − 17y2)
= 14x2 + 8xy + 3y2 − 26x2 + 8xy + 17y2
= (14x2 − 26x2) + (8xy + 8xy) + (3y2 + 17y2)
= −12x2 + 16xy + 20y2
संबंधित प्रश्न
Subtract: −2(xy)2 (y3 + 7x2y + 5) from 5y2 (x2y3 – 2x4y + 10x2)
Subtract: m + n from 3m – 7n
Subtract: 2y + z from 6z – 5y
Subtract – 3ab – 8 from 3ab + 8. Also, subtract 3ab + 8 from – 3ab – 8
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
Subtract:
7p(3q + 7p) from 8p(2p – 7q)
Subtract the following expressions:
–7p2qr from –3p2qr
Subtract the following expressions:
x4 + 3x3y3 + 5y4 from 2x4 – x3y3 + 7y4
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
A + B + C
If P = –(x – 2), Q = –2(y + 1) and R = –x + 2y, find a, when P + Q + R = ax.
