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Suppose X Has a Binomial Distribution `B(6, 1/2)`. Show that X = 3 is the Most Likely Outcome. (Hint: P(X = 3) is the Maximum Among All P (Xi), Xi = 0, 1, 2, 3, 4, 5, 6) - Mathematics

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प्रश्न

Suppose X has a binomial distribution `B(6, 1/2)`. Show that X = 3 is the most likely outcome.

(Hint: P(X = 3) is the maximum among all P (xi), xi = 0, 1, 2, 3, 4, 5, 6)

उत्तर

X is the random variable whose binomial distribution is `B(6, 1/2)`..

Therefore, n = 6 and p = 1/2

The value of `""^6C_3` is maximum. Therefore, for x = 3, P(X = x) is maximum.

Thus, X = 3 is the most likely outcome.

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अध्याय 13: Probability - Exercise 13.5 [पृष्ठ ५७७]

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एनसीईआरटी Mathematics [English] Class 12
अध्याय 13 Probability
Exercise 13.5 | Q 8 | पृष्ठ ५७७

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