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प्रश्न
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, solve the questions given below:
Which of the following orbitals has the lowest energy?
5p, 5d, 5f, 6s, 6p
उत्तर
| Orbitals | n | n + l |
| 5p | 5 | 6 |
| 5d | 5 | 7 |
| 5f | 5 | 8 |
| 6s | 6 | 6 |
| 6p | 6 | 7 |
The highest energy orbital is 5f
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संबंधित प्रश्न
Choose the correct option.
“No two electrons in the same atoms can have identical set of four quantum numbers”. This statement is known as -
State the order of filling atomic orbitals following Aufbau principle.
Write condensed orbital notation of electronic configuration of the following element:
Silicon (Z = 14)
Draw shapes of 2p orbitals.
Indicate the number of unpaired electrons in \[\ce{Si}\] (Z = 14).
Which one of the following orders is CORRECT in case of energy of the given subshells?
P: n = 4; l = 3
Q: n = 5; I = 1
R: n = 5; l = 0
S: n = 4; l = 2
How many electrons can fit in the orbital for which n = 4 and l = 2?
Which one of the following is NOT possible?
Which of the following sets of quantum numbers are correct?
| `n` | `l` | `m_l` | |
| (i) | 1 | 1 | +2 |
| (ii) | 2 | 1 | +1 |
| (iii) | 3 | 2 | –2 |
| (iv) | 3 | 4 | –2 |
The arrangement of orbitals on the basis of energy is based upon their (n + l) value. Lower the value of (n + l), lower is the energy. For orbitals having same values of (n + l), the orbital with lower value of n will have lower energy.
Based upon the above information, arrange the following orbitals in the increasing order of energy.
1s, 2s, 3s, 2p
