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प्रश्न
The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.
योग
उत्तर
Reqd. Area = `1/2` (base) x (altitude)
`=1/2` (3x − 4y) (6x + 5y)
`=1/2 ` (18x2 + 15xy − 24xy − 20y2)
`=1/2` (18x2 − 9xy − 20y2) sq. unit.
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संबंधित प्रश्न
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Evaluate (x5) × (3x2) × (-2x) for x = 1.
Evaluate: (2x – 5y)(2x + 3y) for x = 2 and y = 3.
Evaluate: xz (x2 + y2) for x = 2, y = 1 and z= 1.
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Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.
Multiply and then verify :
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