Advertisements
Advertisements
प्रश्न
Evaluate: (2x – 5y)(2x + 3y) for x = 2 and y = 3.
उत्तर
(2x – 5y) (2x + 3y)
= 2x × 2x − 5y × 2x + 2x × 3y − 5y × 3y
= 4x2 − 10xy + 6xy − 15y2
Hence, x = 2 and y = 3
4x2 − 10xy + 6xy − 15y2
= 4(2)2 − 10(2)(3) + 6(2)(3) − 15(3)2
= 16 − 60 + 36 − 135
= 52 − 195
= −143
APPEARS IN
संबंधित प्रश्न
Multiply: 6x3 − 5x + 10 by 4 − 3x2
Simplify : (4x – 5y) (5x – 4y)
The adjacent sides of a rectangle are x2 – 4xy + 7y2 and x3 – 5xy2. Find its area.
The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.
Find the value of (3x3) × (-5xy2) × (2x2yz3) for x = 1, y = 2 and z = 3.
Evaluate (x5) × (3x2) × (-2x) for x = 1.
If x = 2 and y = 1; find the value of (−4x2y3) × (−5x2y5).
Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.
Multiply and then verify :
−3x2y2 and (x – 2y) for x = 1 and y = 2.
Multiply: (ab – 1) (3 – 2ab)