Advertisements
Advertisements
प्रश्न
Find the value of (3x3) × (-5xy2) × (2x2yz3) for x = 1, y = 2 and z = 3.
उत्तर
For x = 1, y = 2 and z = 3
(3x3) × (−5xy2) × (2x2yz3)
(3 × 13) × (−5 × 1 × 22) × (2 × 12 × 2 × 33)
3 × (−5 × 4) × (2 × 1 × 2 × 27)
3 × (−20) × 108
= −6480
APPEARS IN
संबंधित प्रश्न
Simplify : (7x – 8) (3x + 2)
Simplify : (4x – 5y) (5x – 4y)
Simplify : (3y + 4z) (3y – 4z) + (2y + 7z) (y + z)
The adjacent sides of a rectangle are x2 – 4xy + 7y2 and x3 – 5xy2. Find its area.
The base and the altitude of a triangle are (3x – 4y) and (6x + 5y) respectively. Find its area.
Multiply -4xy3 and 6x2y and verify your result for x = 2 and y= 1.
Evaluate: xz (x2 + y2) for x = 2, y = 1 and z= 1.
Evaluate: 2x(3x – 5) – 5(x – 2) – 18 for x = 2.
Multiply and then verify :
−3x2y2 and (x – 2y) for x = 1 and y = 2.
Multiply: 2x2 – 4x + 5 by x2 + 3x – 7
