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प्रश्न
Find the value of (3x3) × (-5xy2) × (2x2yz3) for x = 1, y = 2 and z = 3.
उत्तर
For x = 1, y = 2 and z = 3
(3x3) × (−5xy2) × (2x2yz3)
(3 × 13) × (−5 × 1 × 22) × (2 × 12 × 2 × 33)
3 × (−5 × 4) × (2 × 1 × 2 × 27)
3 × (−20) × 108
= −6480
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संबंधित प्रश्न
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