Advertisements
Advertisements
प्रश्न
The coordinates of the point P dividing the line segment joining the points A (1, 3) and B (4, 6) in the ratio 2 : 1 are:
विकल्प
A. (2, 4)
B. (3, 5)
C. (4, 2)
D. (5, 3)
उत्तर
Let P(x, y) divides line segment joining A (1, 3) and B (4, 6) in the ratio 2 : 1.
We know that, the coordinates of a point (x, y) dividing the line segment joining the points (x1, y1) and (x2, y2) in the ratio m1 : m2 are given by
`x=(m_1x_2+m_2x_1)/(m_1+m_2)` and `y=(m_1+y_2+m_2y_1)/(m_1+m_2)`
`therefore Here x=(2(4)+1(1))/(2+1)` and `y=(2(6)+1(3))/(2+1)`
`rArrx=9/3 ` and `y=15/3`
`rArrx=3` and `y=3`
Thus, (3, 5) divides the line segment AB in the ratio 2 : 1.
Hence, the correct answer is B.
संबंधित प्रश्न
Find values of k if area of triangle is 4 square units and vertices are (−2, 0), (0, 4), (0, k)
If `a≠ b ≠ c`, prove that the points (a, a2), (b, b2), (c, c2) can never be collinear.
If G be the centroid of a triangle ABC and P be any other point in the plane, prove that PA2+ PB2 + PC2 = GA2 + GB2 + GC2 + 3GP2.
Find the area of a triangle whose sides are respectively 150 cm, 120 cm and 200 cm ?
Show that the points (-3, -3),(3,3) and C (-3 `sqrt(3) , 3 sqrt(3))` are the vertices of an equilateral triangle.
Find the area of Δ ABC whose vertices are:
A (1,2) B (-2,3) and C (-3,-4)
Show that the following points are collinear:
A(-5,1), B(5, 5) and C(10, 7)
If the centroid of ΔABC having vertices A (a,b) , B (b,c) and C (c,a) is the origin, then find the value of (a+b+c).
The points A(2, 9), B(a, 5) and C(5, 5) are the vertices of a triangle ABC right angled at B. Find the values of a and hence the area of ∆ABC.
The dimensions of a rectangle ABCD are 51 cm × 25 cm. A trapezium PQCD with its parallel sides QC and PD in the ratio 9 : 8, is cut off from the rectangle as shown in the following figure. If the area of the trapezium PQCD is `5/6` th part of the area of the rectangle, find the lengths QC and PD.