Advertisements
Advertisements
प्रश्न
The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called ______.
विकल्प
Cell potential
Cell emf
Potential difference
Cell voltage
उत्तर
The difference between the electrode potentials of two electrodes when no current is drawn through the cell is called cell emf.
Explanation:
EMF is the difference between the electrode potentials of two electrodes • when no current is drawn through the cell.
APPEARS IN
संबंधित प्रश्न
Calculate E°cell for the following reaction at 298 K:
2Al(s) + 3Cu+2(0.01M) → 2Al+3(0.01M) + 3Cu(s)
Given: Ecell = 1.98V
Calculate e.m.f of the following cell at 298 K:
2Cr(s) + 3Fe2+ (0.1M) → 2Cr3+ (0.01M) + 3 Fe(s)
Given: E°(Cr3+ | Cr) = – 0.74 VE° (Fe2+ | Fe) = – 0.44 V
Calculate e.m.f. and ∆G for the following cell:
Mg (s) |Mg2+ (0.001M) || Cu2+ (0.0001M) | Cu (s)
`"Given :" E_((Mg^(2+)"/"Mg))^0=−2.37 V, E_((Cu^(2+)"/"Cu))^0=+0.34 V.`
Calculate the emf of the following cell at 25°C :
Which cell will measure standard electrode potential of copper electrode?
Using the data given below find out the strongest reducing agent.
`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖` = 1.33 V `"E"_("Cl"_2//"Cl"^-) = 1.36` V
`"E"_("MnO"_4^-//"Mn"^(2+))` = 1.51 V `"E"_("Cr"^(3+)//"Cr")` = - 0.74 V
Represent the cell in which the following reaction takes place.The value of E˚ for the cell is 1.260 V. What is the value of Ecell?
\[\ce{2Al (s) + 3Cd^{2+} (0.1M) -> 3Cd (s) + 2Al^{3+} (0.01M)}\]
Standard electrode potential of three metals X, Y and Z are – 1.2 V, + 0.5 V and – 3.0 V, respectively. The reducing power of these metals will be:
The potential of a hydrogen electrode at PH = 10 is
Standard reduction potentials (E°) of Cd2+, respectively which is the strongest reducing agent