Advertisements
Advertisements
प्रश्न
The figure shows two circles which intersect at A and B. The centre of the smaller circle is O and lies on the circumference of the larger circle. Given that ∠APB = a°.
Calculate, in terms of a°, the value of : ∠ADB.
Give reasons for your answers clearly.
उत्तर
Join AB.
∠ADB = ∠ACB = 180° – 2a°
(Angle subtended by the same arc on the circle are equal)
APPEARS IN
संबंधित प्रश्न
In the following figure, O is the centre of the circle, ∠AOB = 60° and ∠BDC = 100°. Find ∠OBC.
The figure given below, shows a Circle with centre O.
Given: ∠AOC = a and ∠ABC = b.
Find the relationship between a and b
In a regular pentagon ABCDE, inscribed in a circle; find ratio between angle EDA and angle ADC.
In the figure, O is the centre of the circle and the length of arc AB is twice the length of arc BC. If angle AOB = 108°, find: ∠CAB
In the given figure, chord ED is parallel to diameter AC of the circle. Given ∠CBE = 65°, calculate ∠DEC.
In the given figure, AB is the diameter of the circle with centre O.
If ∠ADC = 32°, find angle BOC.
In the given figure, AC is the diameter of circle, centre O. CD and BE are parallel. Angle AOB = 80o and angle ACE = 10o. Calculate: Angle CED.
In the given figure, AOB is a diameter and DC is parallel to AB. If ∠ CAB = xo ; find (in terms of x) the values of: ∠ DAC
AB is the diameter of the circle with centre O. OD is parallel to BC and ∠ AOD = 60° ; calculate the numerical values of: ∠ DBC
In the given figure, the centre O of the small circle lies on the circumference of the bigger circle. If ∠APB = 75° and ∠BCD = 40°, find : ∠ACB