Advertisements
Advertisements
प्रश्न
The following table shows the frequency distribution of heights of 51 boys:
| Height (cm) | 120 | 121 | 122 | 123 | 124 |
| Frequency | 5 | 8 | 18 | 10 | 9 |
Find the mode of heights.
उत्तर
Mode is 122 cm because it occur maximum number of times. i.e frequency is 18.
APPEARS IN
संबंधित प्रश्न
Calculate the mean of the distribution given below using the shortcut method.
| Marks | 11-20 | 21-30 | 31-40 | 41-50 | 51-60 | 61-70 | 71-80 |
| No. of students | 2 | 6 | 10 | 12 | 9 | 7 | 4 |
If each number given in (a) is diminished by 2, find the new value of mean.
Find the mean of the following frequency distribution :
| Class | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 | 60-70 |
| Frequency | 4 | 4 | 7 | 10 | 12 | 8 | 5 |
Find the mode of the following:
21, 22, 28, 23, 24, 21 26, 22, 29, 27, 21, 21, 26, 24, 23
Find the mode of the following:
3, 4, 5, 7, 6, 3, 5, 4, 3, 5, 6, 4, 7, 5, 4, 5, 4, 3, 4, 5, 7, 6, 5, 6, 6, 7
Estimate the median, the lower quartile and the upper quartile of the following frequency distribution by drawing an ogive:
| Age( in yrs) | Under 10 | Under 20 | Under 30 | Under 40 | Under 50 | Under 60 |
| No. of males | 6 | 10 | 25 | 32 | 43 | 50 |
The mean of marks scored by 100 students was found to be 40, later on, it was discovered that a score of 53 was misread as 83. Find the correct mean.
Find the median of the following sets of numbers.
15, 8, 14, 20, 13, 12, 16
The median class for the given distribution is:
| Class Interval | 1 - 5 | 6 - 10 | 11 - 15 | 16 - 20 |
| Cumulative Frequency | 2 | 6 | 11 | 18 |
In a given data, arranged in ascending or descending order, the middle most observation is called ______.
