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प्रश्न
The heights (in cm) of 30 students of class IX are given below:
155, 158, 154, 158, 160, 148, 149, 150, 153, 159, 161, 148, 157, 153, 157, 162, 159, 151, 154, 156, 152, 156, 160, 152, 147, 155, 163, 155, 157, 153
Prepare a frequency distribution table with 160-164 as one of the class intervals.
उत्तर
One of the class intervals is 160–164. This means that class size is 4
Here, the maximum and minimum values of the variate are 163 and 147 respectively.
So the range = 163 – 147 = 16
Here, we will take class size 4. So we must have 5 classes each of size 4
Lower limit of first class interval is;
`a-h/2=147-4/2=145`
And, upper limit of first class interval is:
`a + h/2=147+ 4/2=149`
Therefore, the frequency distribution in which the lower limit is included and upper limit excluded is:
Height (in cm) | Tally marks | Frequency |
144-148 | | | 1 |
148-152 | ||||| | 5 |
152-156 | ||||| ||||| | 10 |
156-160 | ||||| |||| | 9 |
160-164 | ||||| | 5 |
Total | 30 |
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