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प्रश्न
The line segment joining A (2, 3) and B (6, – 5) is intersected by the X axis at the point K. Write the ordinate of the point K. Hence find the ratio in which K divides AB.
उत्तर
A (2, 3) and B (6,- 5)
Intersected at X axis at K.
∴ y = 0 or ordinate = 0
K (x, 0)
Let required ratio be a: 1
∴ Ordinate of K = 0
0 = `(a xx -5 + 1 xx 3)/(a + 1)`
0 = -5a + 3
5a = 3, a = `(3)/(5)`
∴ K divides AB in ratio of 3 : 5.
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संबंधित प्रश्न
Calculate the co-ordinates of the point P which divides the line segment joining: A (–4, 6) and B (3, –5) in the ratio 3 : 2
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= `a(1/t^2 + 1) = (a(t^2 + 1))/t^2`
Now `(1)/"SP" + (1)/"SQ" = (1)/(a(t^2 + 1)) + (1 xx t^2)/(a(t^2 + 1)`
= `((1 + t^2))/(a(t^2 + 1)`
`(1)/"SP" + (1)/"SQ" = (1)/a`.
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From the adjacent figure:
(i) Write the coordinates of the points A, B, and
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(iii) Line through C, drawn parallel to AB, intersects Y-axis at D. Calculate the co-ordinates of D.