Advertisements
Advertisements
प्रश्न
The ratio of masses of two planets is 2:3 and the ratio of their radii is 4:7 Find the ratio of their accelerations due to gravity.
उत्तर
The ratio of masses of two planets m1: m2 = 2 : 3
The ratio of radii of two planets R1: R2 = 4: 7
Formula:
g= `"GM"/R^2` ∴ g ∝ `"M"/"R"^2`
`"g"_1/"g"_2` = `"M"_1/"M"_2` . `"R"_2^2/"R"_1^2` = `2/3xx 7^2/4^2` = `(2xx49)/(3xx16)` = `98/48`
`"g"_1/"g"_2` = `49/24`
APPEARS IN
संबंधित प्रश्न
State whether the following statement is true or false :
The value of G on the moon is about one-sixth `(1/6)`of the value of G on the earth.
The radius of planet A is half the radius of planet B. If the mass of A is MA, what must be the mass of B so that the value of g on B is half that of its value on A?
The CGS unit of G is dyne.cm2/g2.
______ is used to change the speed of the car.
The depth 'd' below the surface of the earth at which acceleration due to gravity becomes `(g/n)` is ______.
R = radius of the earth, 'g' = acceleration due to gravity, n = integer
When the value of acceleration due to gravity 'g' becomes `(g/3)` above the earth's surface at height 'h' then relation between 'h' and 'R' is ______.
R =radius of the earth
On the earth, a stone is thrown from a height in a direction parallel to the earth’s surface while another stone is simultaneously dropped from the same height. Which stone would reach the ground first and why?
Suppose the gravity of the earth suddenly becomes zero, then in which direction will the moon begin to move if no other celestial body affects it?
The moon has a mass of 1/81 that of the earth and a radius of 1/4 that of the earth. The escape speed from the surface of the earth is 11.2 km/s. The escape speed from the surface of the moon is ______.
The value of gravitational acceleration g at a height h above the earth's surface is `"g"/4`, then ______. (R = radius of earth)