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The thickness of a hollow metallic cylinder is 2 cm. It is 70 cm long with outer radius of 14 cm. Find the volume of the metal used in making the cylinder, assuming that it is open at both the - Mathematics

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प्रश्न

The thickness of a hollow metallic cylinder is 2 cm. It is 70 cm long with outer radius of 14 cm. Find the volume of the metal used in making the cylinder, assuming that it is open at both the ends. Also find its weight if the metal weighs 8 g per cm3.

योग

उत्तर

The thickness of the hollow metallic cylinder is 2 cm.

Height of the cylinder = 70 cm

Outer radius of the cylinder = 14 cm

Inner radius of the cylinder = 14 – 2 = 12 cm


Volume of the metal used in making the cylinder = Volume of the hollow cylinder

= π(R2 – r2) × h

= `22/7 xx [(14)^2 - (12)^2] xx 70`

= 22 × [196 – 144] × 10

= 22 × 52 × 10

= 11440 cm3

Weight of 11440 cm3, If metal is 8 g per cm3

= 11440 × 8

= 91520 g

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अध्याय 11: Mensuration - Exercise [पृष्ठ ३५६]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 8
अध्याय 11 Mensuration
Exercise | Q 91. | पृष्ठ ३५६

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