Advertisements
Advertisements
प्रश्न
Three consecutive natural numbers are such that the square of the first increased by the product of other two gives 154. Find the numbers.
उत्तर
Let the numbers be x-1, x, x+l . Then as per question,
(x-1)2 + (x) (x+l ) = 154
⇒ x2 -2x + 1+ x2 +x =154
⇒ 2 x2 - x - 153 = 0
⇒ 2 x2 - 18x +17x - 153 = 0
⇒ 2x (x-9) + 17 (x-9) = 0
⇒ (2x+17) (x-9) = 0
⇒ As the number have to be natural number, x=9
Hence, the numbers are 8,9 ,10 .
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation for x:
`x^2+(a/(a+b)+(a+b)/a)x+1=0`
Solve the equation:`14/(x+3)-1=5/(x+1); xne-3,-1` , for x
Solve the following quadratic equations by factorization:
`(x-1)/(2x+1)+(2x+1)/(x-1)=5/2` , x ≠ -1/2, 1
The sum of the squares of two numbers as 233 and one of the numbers as 3 less than twice the other number find the numbers.
The sum of two numbers is 9. The sum of their reciprocals is 1/2. Find the numbers.
A takes 10 days less than the time taken by B to finish a piece of work. If both A and B together can finish the work in 12 days, find the time taken by B to finish the work.
If 1 is a root of the quadratic equation \[3 x^2 + ax - 2 = 0\] and the quadratic equation \[a( x^2 + 6x) - b = 0\] has equal roots, find the value of b.
If 2 is a root of the equation x2 + ax + 12 = 0 and the quadratic equation x2 + ax + q = 0 has equal roots, then q =
The values of k for which the quadratic equation \[16 x^2 + 4kx + 9 = 0\] has real and equal roots are
Solve the following equation by factorization
`(x^2 - 5x)/(2)` = 0
