हिंदी

To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below: - Mathematics

Advertisements
Advertisements

प्रश्न

To find out the concentration of SO2 in the air (in parts per million, i.e., ppm), the data was collected for 30 localities in a certain city and is presented below:

concentration of SO2 (in ppm) Frequency
0.00 − 0.04 4
0.04 − 0.08 9
0.08 − 0.12 9
0.12 − 0.16 2
0.16 − 0.20 4
0.20 − 0.24 2

Find the mean concentration of SO2 in the air.

योग

उत्तर

To find the class marks for each interval, the following relation is used:

`x_i  = ("Upper class limit + Lower class limit")/2`

Class size of this data = 0.04

Taking 0.14 as the assumed mean (a), di, ui, fiui are calculated as follows:

Concentration of SO2 (in ppm)

Frequency fi

Class mark xi

d= xi − 0.14 `u_i=(x_i-0.14)/0.04` fiui
0.00 − 0.04 4 0.02 −0.12  −3 −12
0.04 − 0.08 9 0.06 −0.08 −2 −18
0.08 − 0.12 9 0.10 −0.04 −1 −9
0.12 − 0.16 2 0.14 0 0 0
0.16 − 0.20 4 0.18 0.04 1 4
0.20 − 0.24 2 0.22 0.08 2 4
Total 30       −31

From the table, we obtain

`sumf_i = 30`

`sumf_iu_i = -31`

mean `barx=a+(sumf_iu_i)/(sumf_i)xxh`

`= 0.14 + ((-31)/30)(0.04)`

= 0.14 − 0.04133

= 0.09867

= 0.099 ppm

Therefore, mean concentration of SO2 in the air is 0.099 ppm.

shaalaa.com
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 14: Statistics - Exercise 14.1 [पृष्ठ २७१]

APPEARS IN

एनसीईआरटी Mathematics [English] Class 10
अध्याय 14 Statistics
Exercise 14.1 | Q 7 | पृष्ठ २७१
आरडी शर्मा Mathematics [English] Class 10
अध्याय 15 Statistics
Exercise 15.3 | Q 23 | पृष्ठ २४

संबंधित प्रश्न

A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.

Number of plants 0 - 2 2 - 4 4 - 6 6 - 8 8 - 10 10 - 12 12 - 14
Number of houses 1 2 1 5 6 2 3

Which method did you use for finding the mean, and why?


Consider the following distribution of daily wages of 50 worker of a factory.

Daily wages (in Rs)

100­ − 120

120­ − 140

140 −1 60

160 − 180

180 − 200

Number of workers

12

14

8

6

10

Find the mean daily wages of the workers of the factory by using an appropriate method.


The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs.18. Find the missing frequency f.

Daily pocket allowance (in Rs 11 - 13 13 - 15 15 - 17 17 - 19 19 - 21 21 - 23 23 - 25
Number of workers 7 6 9 13 f 5 4

Calculate the mean for the following distribution:-

x 5 6 7 8 9
f 4 8 14 11 3

If the mean of the following data is 20.6. Find the value of p.

x 10 15 P 25 35
f 3 10 25 7 5

Find the mean of each of the following frequency distributions

Class interval 25 - 35 35 - 45 45 - 55 55 - 65 65 - 75
Frequency 6 10 8 12 4

Find the mean of the following data, using direct method:

Class 25-35 35-45 45-55 55-65 65-75
Frequency 6 10 8 12 4

Find the mean of the following data, using direct method:

Class 0-100 100-200 200-300 300-400 400-500
Frequency  6 9 15 12 8

If the mean of the following frequency distribution is 24, find the value of p.

Class 0-10 10-20 20-30 30-40 40-50
Frequency 3 4 p 3 2

The mean of the following frequency data is 42, Find the missing frequencies x and y if the sum of frequencies is 100

Class 

interval 

0-10 10-20 20-30 30-40 40-50 50-60 60-70 70-80
Frequency 7 10 x 13 y 10 14 9

Find x and y.


Find the mean of the following data, using assumed-mean method:

Class 0 – 20 20 – 40 40 – 60 60 – 80 80 – 100 100 - 120
Frequency 20 35 52 44 38 31

Mean of a certain number of observation is `overlineX`.  If each observation is divided by m(m ≠ 0) and increased by n, then the mean of new observation is


The following table shows the weight of 12 students:

Weight in kg. 67 70 72 73 75
Number of students 4 3 2 2 1

Find the Mean weight.


An analysis of particular information is given in the following table.

Age Group 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50
Frequency 2 5 6 5 2

For this data, mode = median = 25. Calculate the mean. Observing the given frequency distribution and values of the central tendency interpret your observation.


Find the mean of the following frequency distribution:

Class 1 – 5 5 – 9 9 – 13 13 – 17
Frequency 4 8 7 6

250 apples of a box were weighed and the distribution of masses of the apples is given in the following table:

Mass
(in grams)
80 – 100 100 – 120 120 – 140 140 – 160 160 – 180
Number of
apples
20 60 70 x 60

Find the value of x and the mean mass of the apples.


Which of the following cannot be determined graphically for a grouped frequency distribution?


The following table gives the duration of movies in minutes:

Duration 100 – 110 110 – 120 120 – 130 130 – 140  140 – 150 150 – 160
No. of movies 5 10 17 8 6 4

Using step-deviation method, find the mean duration of the movies.


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×