Advertisements
Advertisements
प्रश्न
Two chords AB and AC of a circle with centre O are on the opposite sides of OA. Then ∠OAB = ∠OAC .
विकल्प
True
False
उत्तर
This statement is False.
Explanation:
We have,
In ΔOAB and ΔOAC,
OA = OA ...[Common]
OB = OC ...[Radii of a same circle]
Here, we are not able to show that either any angle or third side is equal and ΔOAB is not congruent to ΔOAC.
∴ ∠OAB ≠ ∠OAC
APPEARS IN
संबंधित प्रश्न
Two circles of radii 5 cm and 3 cm intersect at two points and the distance between their centres is 4 cm. Find the length of the common chord.
If two equal chords of a circle intersect within the circle, prove that the line joining the point of intersection to the centre makes equal angles with the chords.
true or false
If a circle is divided into three equal arcs each is a major arc.
An equilateral triangle of side 9cm is inscribed in a circle. Find the radius of the circle.
If two diameters of a circle intersect each other at right angles, then quadrilateral formed by joining their end points is a
Angle formed in minor segment of a circle is
Two congruent circles with centres O and O′ intersect at two points A and B. Then ∠AOB = ∠AO′B.
If two equal chords of a circle intersect, prove that the parts of one chord are separately equal to the parts of the other chord.
Two equal chords AB and CD of a circle when produced intersect at a point P. Prove that PB = PD.
AB and AC are two chords of a circle of radius r such that AB = 2AC. If p and q are the distances of AB and AC from the centre, prove that 4q2 = p2 + 3r2.
