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Two Dice Are Thrown. Find the Probability that the Numbers Appeared Has the Sum 8, If It is Known that the Second Die Always Exhibits 4. - Mathematics

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प्रश्न

Two dice are thrown. Find the probability that the numbers appeared has the sum 8, if it is known that the second die always exhibits 4.

उत्तर

Consider the given events.
A = 4 appears on second die
B = The sum of the numbers on two dice is 8.

Clearly,
A = {(1, 4), (2, 4), (3, 4), (4, 4) (5, 4) (6, 4)}
B = {(4, 4), (3, 5), (5, 3) (2, 6), (6, 2)}

\[\text{ Now } , \]
\[A \cap B = \left\{ \left( 4, 4 \right) \right\}\]
\[ \therefore \text{ Required probability } = P\left( B/A \right) = \frac{n\left( A \cap B \right)}{n\left( A \right)} = \frac{1}{6}\]

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Probability Examples and Solutions
  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 31: Probability - Exercise 31.3 [पृष्ठ ३४]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 31 Probability
Exercise 31.3 | Q 13 | पृष्ठ ३४

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