हिंदी

Use the data given in below find out which of the following is the strongest oxidising agent. E0cr2O12-Cr3+ = 1.33 V E0Cl2Cl- = 1.36 V E0MnO4-MN2+ = 1.51 V E0Cr3+Cr = – 0.74 V - Chemistry

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प्रश्न

Use the data given in below find out which of the following is the strongest oxidising agent.

`"E"_("Cr"_2"O"_7^(2-)//"Cr"^(3+))^⊖`= 1.33 V `"E"_("Cl"_2//"Cl"^-)^⊖` = 1.36 V

`"E"_("MnO"_4^-//"Mn"^(2+))^⊖` = 1.51 V `"E"_("Cr"^(3+)//"Cr")^⊖` = - 0.74 V

विकल्प

  • Cl 

  • Mn2+ 

  • `"MNO"_4^-`

  • Cr3+ 

MCQ

उत्तर

`"MNO"_4^-`

Explanation:

The higher the positive value of standard reduction potential of metal ion, the higher will be its oxidizing capacity.

Since, `"E"_("MnO"_4^-//"Mn"^(2+))^⊖` has value equal to 1.51 V hence it is the strongest oxidizing agent.

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अध्याय 3: Electrochemistry - Exercises [पृष्ठ ३५]

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एनसीईआरटी एक्झांप्लर Chemistry [English] Class 12
अध्याय 3 Electrochemistry
Exercises | Q I. 9. | पृष्ठ ३५

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