Advertisements
Advertisements
प्रश्न
Using remainder theorem, find the remainder on dividing f(x) by (x + 3) where f(x) = 2x2 – 5x + 1
उत्तर
Let x + 3 = 0
⇒ x = -3
Substituting the value of x in f(x),
f(x) = 2x2 – 5x + 1
∴ f(-3) = 2(-3)2 - 5(-3) + 1
= 18 + 15 + 1
= 34.
Hence Reminder = 34.
APPEARS IN
संबंधित प्रश्न
The expression 2x3 + ax2 + bx – 2 leaves remainder 7 and 0 when divided by 2x – 3 and x + 2 respectively. Calculate the values of a and b.
Using the Remainder Theorem, factorise the following completely:
x3 + x2 – 4x – 4
The polynomials ax3 + 3x2 – 3 and 2x3 – 5x + a, when divided by x – 4, leave the same remainder in each case. Find the value of a.
When divided by x – 3 the polynomials x3 – px2 + x + 6 and 2x3 – x2 – (p + 3) x – 6 leave the same remainder. Find the value of ‘p’.
If p(x) = 4x3 - 3x2 + 2x - 4 find the remainderwhen p(x) is divided by:
x + 2
Find the remainder (without division) when 2x3 – 3x2 + 7x – 8 is divided by x – 1 (2000)
If x + 1 is a factor of 3x3 + kx2 + 7x + 4, then the value of k is
For what value of m is x3 – 2mx2 + 16 divisible by x + 2?
If x25 + x24 is divided by (x + 1), the result is ______.
4x2 – kx + 5 leaves a remainder 2 when divided by x – 1. The value of k is ______.
