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Water in canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. how much area will it irrigate in 30 minutes, if 8 cm of standing water is needed? - Mathematics

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प्रश्न

Water in canal, 6 m wide and 1.5 m deep, is flowing with a speed of 10 km/h. how much area will it irrigate in 30 minutes, if 8 cm of standing water is needed?

उत्तर

Consider an area of cross-section of canal as ABCD.

Area of cross-section = 6 × 1.5 = 9 m2

Speed of water = 10 km/h = 10000/60 metre/min

Volume of water that flows in 1 minute from canal = 9 x 10000/60 =1500 m3

Volume of water that flows in 30 minutes from canal = 30 × 1500 = 45000 m3

Let the irrigated area be A. Volume of water irrigating the required area will be equal to the volume of water that flowed in 30 minutes from the canal.

Vol. of water flowing in 30 minutes from canal = Vol. of water irrigating the reqd. area

4500 = (Ax8)/100

A = 562500 m2

Therefore, area irrigated in 30 minutes is 562500 m2.

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अध्याय 13: Surface Areas and Volumes - Exercise 13.3 [पृष्ठ २५२]

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एनसीईआरटी Mathematics [English] Class 10
अध्याय 13 Surface Areas and Volumes
Exercise 13.3 | Q 8 | पृष्ठ २५२

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