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प्रश्न
What is the general solution of the differential equation `e^(y') = x`?
विकल्प
y = xlogx + c
y = xlogx − x + c
y = xlogx + x + c
y = x + c
MCQ
उत्तर
y = xlogx − x + c
Explanation:
The given differential equation `e^(y') = x => dy/dx = logx`
`dy = logxdx => intdy = int logxdx`
y = xlogx − x + c
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