Question

What is the general solution of the differential equation `e^(y') = x`?

Options

• y = xlogx + c

• y = xlogx − x + c

• y = xlogx + x + c

• y = x + c

Answer 1

y = xlogx − x + c

Explanation:

The given differential equation `e^(y') = x => dy/dx = logx` 

`dy = logxdx => intdy = int logxdx`

y = xlogx − x + c