Advertisements
Advertisements
प्रश्न
What is the probability that a leap year has 53 Sundays?
उत्तर
A leap year has 366 days i.e., 52 weeks and 2 days.
There are 52 Sundays in 52 weeks.
For the remaining 2 days,
Sample space is
S = {(Mon., Tue.), (Tue., Wed.), (Wed., Thur.),
(Thur., Fri.), (Fri., Sat.), (Sat., Sun.), (Sun., Mon.)}
∴ n(S) = 7
Let A be the event that the remaining two days are Sundays.
∴ A = {(Sat., Sun.), (Sun., Mon.)}
∴ n(A) = 2
∴ P(A) = `("n"("A"))/("n"("S"))`
∴ P(A) = `2/7`
∴ The probability that a leap year has 53 Sundays is `2/7`.
APPEARS IN
संबंधित प्रश्न
Choose the correct alternative answer for the following question and write the alphabet.
Which of the following number cannot represent a probability?
What is the probability of the event that a number chosen from 1 to 50 is a prime number?
Which of the following options shows the highest probability?
If one die is rolled, then find the probability of the following event by completing the activity.
Event A: The number on the upper face is prime.
Activity: Let ‘S’ be the sample space.
S = {1, 2, 3, 4, 5, 6}
∴ n(S) = 6
Event A: Prime number on the upper face.
A = {`square`}
∴ n(A) = 3
P(A) = `square/(n(S))` .....[Formula]
= `square/6`
∴ P(A) = `1/square`
A card is drawn from a well shuffled pack of 52 playing cards. Find the probability of the event, the card drawn is a red card.
Activity: Let ‘S’ be the sample space.
∴ n(S) = 52
Event A: Card drawn is a red card.
∴ Total red cards = `square` hearts + 13 diamonds
∴ n(A) = `square`
∴ P(A) = `square/(n("S"))` ......[Formula]
P(A) = `26/52`
P(A) = `square`
In Adarsh High School, out of 30 students in a class 3 students wear glasses (spectacles). If a student in the class is randomly selected, find the probability that he or she wears glasses (spectacles) by completing the following activity
Activity: There are a total of 30 students in the class.
∴ n(S) = `square`
Event: A selected student wears glasses (spectacles).
∴ n(A) = `square`
P(A) = `square/("n"("S"))` ......[Formula]
P(A) = `square`
If three coins are tossed simultaneously, find the probability of the event to get no head
There are 30 cards in a box, each bearing one of the numbers from 1 to 30. One card is drawn at random from the box. Find the probability of event that the card drawn shows a number which is a multiple of 5
If One coin and one die are thrown simultaneously, find the probability of the following events.
Event A: To get a tail and an even number
A box contains 36 cards, bearing only one number from 1 to 36 on each. If one card is drawn at random, find the probability of an event that the card drawn bears, a prime number
A box contains 36 cards, bearing only one number from 1 to 36 on each. If one card is drawn at random, find the probability of an event that the card drawn bears, a number divisible by 3
A bag contains 5 white balls and some blue balls. If the probability of drawing a blue ball is double that of a white ball, determine the number of blue balls in the bag
A bag contains 8 red balls and some blue balls. If one ball is drawn randomly the probability of drawing a red ball to a blue ball are in the ratio 5 : 2, determine the probability of drawing a blue ball from the bag.
A bag contains 8 red and some blue balls. One ball is drawn at random from the bag. If ratio of probability of getting red ball and blue ball is 2:5, then find the number of blue balls.
Using the digits 0, 2, 3, 5 the two-digit numbers are constructed without repetition of digits. Find the probability of the following events:
Condition for event A: The number formed is even.
An urn contains 12 red balls, 15 yellow balls and 18 blue balls. A ball is choosen at random, then to find the probability of choosing a blue and red coloured balls, fill in the boxes.
Total number of balls = 12 + `square` + `square` = `square`
(1) Let E be the event that the choosen ball is blue.
Number of blue balls = `square`
Thus,
P(E) = `"Number of blue balls"/"Total number of balls"`
= `square/square`
(2) Let F be the event that the choosen ball is red.
Number of red balls = `square`
Thus,
P(F) = `square/"Total number of balls"`
= `square/square`
A coin is tossed twice and the four possible outcomes are assumed to be equally likely. If A is the event, 'both head and tail have appeared' and B the event,' at most one tail is observed,' then the value of P(B/A) is ______.
A two digit number is formed with digits 2, 3, 5, 7, 9 without repetition. What is the probability of the following events?
Event A : The number formed is an odd number.
Event B : The number formed is a multiple of 5.
One coin and a die are thrown simultaneously. Find the probability of the following event:
Event A: To get a head and a prime number.
