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What Will Be the Units Digit of the Square of the Following Number? 53924 - Mathematics

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प्रश्न

What will be the units digit of the square of the following number?

 53924

उत्तर

The units digit is affected only by the last digit of the number.  we only need to examine the square of its last digit. 

Its last digit is 4. Hence, the units digit is the last digit of 16 (16 = 42), which is 6.

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 3: Squares and Square Roots - Exercise 3.2 [पृष्ठ १९]

APPEARS IN

आरडी शर्मा Mathematics [English] Class 8
अध्याय 3 Squares and Square Roots
Exercise 3.2 | Q 4.9 | पृष्ठ १९

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संबंधित प्रश्न

What will be the units digit of the square of the following number? 

 78367 


Observe the following pattern 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) = \frac{2 \times 3 \times 4}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) = \frac{3 \times 4 \times 5}{3}\] 

\[\left( 1 \times 2 \right) + \left( 2 \times 3 \right) + \left( 3 \times 4 \right) + \left( 4 \times 5 \right) = \frac{4 \times 5 \times 6}{3}\] 

and find the value of(1 × 2) + (2 × 3) + (3 × 4) + (4 × 5) + (5 × 6)


Observe the following pattern \[1^2 = \frac{1}{6}\left[ 1 \times \left( 1 + 1 \right) \times \left( 2 \times 1 + 1 \right) \right]\]
\[ 1^2 + 2^2 = \frac{1}{6}\left[ 2 \times \left( 2 + 1 \right) \times \left( 2 \times 2 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 = \frac{1}{6}\left[ 3 \times \left( 3 + 1 \right) \times \left( 2 \times 3 + 1 \right) \right]\]
\[ 1^2 + 2^2 + 3^2 + 4^2 = \frac{1}{6}\left[ 4 \times \left( 4 + 1 \right) \times \left( 2 \times 4 + 1 \right) \right]\] and find the values :  

12 + 22 + 32 + 4+ ... + 102

 

 


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Find the squares of the following numbers using diagonal method: 

 273


Find the squares of the following numbers using diagonal method: 

295


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