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प्रश्न
Without solving, comment upon the nature of roots of the following equation:
6x2 – 13x + 4 = 0
उत्तर
6x2 – 13x + 4 = 0
a = 6, b = −13 and c = 4
∴ Discriminant = b2 – 4ac
= (−13)2 – 4(6)(4)
= 169 – 96
= 73
Since 73 is not a perfect square, roots are irrational
Since D > 0, then equation has two real and unequal roots.
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