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Introduction to Trigonometry
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Internal Assessment
Notes
The mode of a list of data values is simply the most common value. Eg. find the mode of the ungrouped data 2, 3, 4, 4, 3, 9, 6, 3, 5, 3
Here the mode is 4 because the highest frequently occured number is 4.
But this was about ungrouped data. In this concept we will learn to find mode of a grouped data. The mode of a grouped data is found with the help of formula.
Mode= `l+ [(f1-fo)/ (2f1-fo-f2)] xx h`
where, l= lower limit of modal class
f1= frequency of the modal class
fo i.e f not= frequency of the class preceeding the modal class
f2= frequency of the class succeeding the modal class
h= Class size= Upper limit- Lower limit
Let's take a example for better understanding,
Find the mode of the given data:
Family size |
1-3 |
3-5 |
5-7 |
7-9 |
9-11 |
No. of families |
7 |
8 |
2 |
2 |
1 |
Solution:
The maximum frequency is 8
Therefore, Modal class= 3-5,
then l= 3, h=2, f1=8, fo=7, f=2
`Mode= l+ [(f1-fo)/ (2f1-fo-f2)] xx h`
= `3+ [(8-7)/ (16-7-2)] xx 2`
= `3+ (1 xx 2)/7`
= `3+ 0.285`
Mode= 3.285
Related QuestionsVIEW ALL [84]
For the following distribution
C.I. | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
F | 20 | 30 | 24 | 40 | 18 |
the sum of lower limits of the modal class and the median class is?
The shirt sizes worn by a group of 200 persons, who bought the shirt from a store, are as follows:
Shirt size: | 37 | 38 | 39 | 40 | 41 | 42 | 43 | 44 |
Number of persons: | 15 | 25 | 39 | 41 | 36 | 17 | 15 | 12 |
Find the model shirt size worn by the group.
The agewise participation of students in the annual function of a school is shown in the following distribution.
Age (in years) | 5 - 7 | 7 - 9 | 9 - 11 | 11 – 13 | 13 – 15 | 15 – 17 | 17 – 19 |
Number of students | x | 15 | 18 | 30 | 50 | 48 | x |
Find the missing frequencies when the sum of frequencies is 181. Also find the mode of the data.
Heights of students of class X are givee in the flowing frequency distribution
Height (in cm) | 150 – 155 | 155 – 160 | 160 – 165 | 165 – 170 | 170 - 175 |
Number of students | 15 | 8 | 20 | 12 | 5 |
Find the modal height.
Also, find the mean height. Compared and interpret the two measures of central tendency.
Find the mode of the following data.
Class interval | 0 - 10 | 10 - 20 | 20 - 30 | 30 - 40 | 40 - 50 |
Frequency | 7 | 13 | 14 | 5 | 11 |
The following data gives the distribution of total monthly household expenditure of 200 families of a village. Find the modal monthly expenditure of the families. Also, find the mean monthly expenditure.
Expenditure (in Rs) | Number of families |
1000 − 1500 | 24 |
1500 − 2000 | 40 |
2000 − 2500 | 33 |
2500 − 3000 | 28 |
3000 − 3500 | 30 |
3500 − 4000 | 22 |
4000 − 4500 | 16 |
4500 − 5000 | 7 |
For the following distribution:
Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 |
Frequency | 10 | 15 | 12 | 20 | 9 |
The sum of lower limits of the median class and modal class is:
If mode of the following frequency distribution is 55, then find the value of x.
Class | 0 – 15 | 15 – 30 | 30 – 45 | 45 – 60 | 60 – 75 | 75 – 90 |
Frequency | 10 | 7 | x | 15 | 10 | 12 |