मराठी

For the following distribution: Class 0 – 5 5 – 10 10 – 15 15 – 20 20 – 25 Frequency 10 15 12 20 9 The sum of lower limits of the median class and modal class is: - Mathematics

Advertisements
Advertisements

प्रश्न

For the following distribution:

Class 0 – 5 5 – 10 10 – 15 15 – 20 20 – 25
Frequency 10 15 12 20 9

The sum of lower limits of the median class and modal class is:

पर्याय

  • 15

  • 25

  • 30

  • 35

MCQ

उत्तर

25

Explanation:

Class Frequency Cumulative Frequency
0 – 5 10 10
5 – 10 15 25
10 – 15 12 37
15 – 20 20 57
20 – 25 9 66

From the table, `N/2 = 66/2 = 33`, which lies in the interval 10 – 15.

Hence, lower limit of the median class is 10.

The highest frequency is 20, which lies in between the interval 15 – 20.

Hence, lower limit of modal class is 15.

Therefore, required sum is 10 + 15 = 25.

shaalaa.com
  या प्रश्नात किंवा उत्तरात काही त्रुटी आहे का?
पाठ 13: Statistics and Probability - Exercise 13.1 [पृष्ठ १५८]

APPEARS IN

एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
पाठ 13 Statistics and Probability
Exercise 13.1 | Q 6 | पृष्ठ १५८
आरडी शर्मा Mathematics [English] Class 10
पाठ 15 Statistics
Exercise 15.8 | Q 38 | पृष्ठ ६९

संबंधित प्रश्‍न

The following table shows the ages of the patients admitted in a hospital during a year:

Age (in years) 5 − 15 15 − 25 25 − 35 35 − 45 45 − 55 55 − 65
Number of patients 6 11 21 23 14 5

Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.


The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.

Runs scored Number of batsmen
3000 − 4000 4
4000 − 5000 18
5000 − 6000 9
6000 − 7000 7
7000 − 8000 6
8000 − 9000 3
9000 − 10000 1
10000 − 11000 1

Find the mode of the data.


The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.

Monthly consumption (in units) Number of consumers
65 - 85 4
85 - 105 5
105 - 125 13
125 - 145 20
145 - 165 14
165 - 185 8
185 - 205 4

Compare the modal ages of two groups of students appearing for an entrance test:

Age (in years): 16-18 18-20 20-22 22-24 24-26
Group A: 50 78 46 28 23
Group B: 54 89 40 25 17

The following is the distribution of height of students of a certain class in a certain city:

Height (in cm): 160 - 162 163 - 165 166 - 168 169 - 171 172 - 174
No. of students: 15 118 142 127 18

Find the average height of maximum number of students.


Find the mean, median and mode of the following data: 

Classes: 0 – 50 50 – 100 100 – 150 150 – 200 200 – 250 250 – 300 300 – 350
Frequency: 2 3 5 6 5 3 1

Find the mode of the following distribution:

Class
interval
10 – 14 14 – 18 18 – 22 22 – 26 26 – 30 30 – 34 34 – 38 38 – 42
Frequency 8 6 11 20 25 22 10 4

 

 


Mode is


If mode of a series exceeds its mean by 12, then mode exceeds the median by


For the following distribution

C.l. 0 - 5 5 - 10 10 - 15 15 - 20 20 - 25
f 10 15 12 20 9

the difference of the upper limit of the median class and the lower limit of the modal class is?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×