Advertisements
Advertisements
प्रश्न
For the following distribution:
Class | 0 – 5 | 5 – 10 | 10 – 15 | 15 – 20 | 20 – 25 |
Frequency | 10 | 15 | 12 | 20 | 9 |
The sum of lower limits of the median class and modal class is:
पर्याय
15
25
30
35
उत्तर
25
Explanation:
Class | Frequency | Cumulative Frequency |
0 – 5 | 10 | 10 |
5 – 10 | 15 | 25 |
10 – 15 | 12 | 37 |
15 – 20 | 20 | 57 |
20 – 25 | 9 | 66 |
From the table, `N/2 = 66/2 = 33`, which lies in the interval 10 – 15.
Hence, lower limit of the median class is 10.
The highest frequency is 20, which lies in between the interval 15 – 20.
Hence, lower limit of modal class is 15.
Therefore, required sum is 10 + 15 = 25.
APPEARS IN
संबंधित प्रश्न
The following table shows the ages of the patients admitted in a hospital during a year:
Age (in years) | 5 − 15 | 15 − 25 | 25 − 35 | 35 − 45 | 45 − 55 | 55 − 65 |
Number of patients | 6 | 11 | 21 | 23 | 14 | 5 |
Find the mode and the mean of the data given above. Compare and interpret the two measures of central tendency.
The given distribution shows the number of runs scored by some top batsmen of the world in one-day international cricket matches.
Runs scored | Number of batsmen |
3000 − 4000 | 4 |
4000 − 5000 | 18 |
5000 − 6000 | 9 |
6000 − 7000 | 7 |
7000 − 8000 | 6 |
8000 − 9000 | 3 |
9000 − 10000 | 1 |
10000 − 11000 | 1 |
Find the mode of the data.
The following frequency distribution gives the monthly consumption of electricity of 68 consumers of a locality. Find the median, mean and mode of the data and compare them.
Monthly consumption (in units) | Number of consumers |
65 - 85 | 4 |
85 - 105 | 5 |
105 - 125 | 13 |
125 - 145 | 20 |
145 - 165 | 14 |
165 - 185 | 8 |
185 - 205 | 4 |
Compare the modal ages of two groups of students appearing for an entrance test:
Age (in years): | 16-18 | 18-20 | 20-22 | 22-24 | 24-26 |
Group A: | 50 | 78 | 46 | 28 | 23 |
Group B: | 54 | 89 | 40 | 25 | 17 |
The following is the distribution of height of students of a certain class in a certain city:
Height (in cm): | 160 - 162 | 163 - 165 | 166 - 168 | 169 - 171 | 172 - 174 |
No. of students: | 15 | 118 | 142 | 127 | 18 |
Find the average height of maximum number of students.
Find the mean, median and mode of the following data:
Classes: | 0 – 50 | 50 – 100 | 100 – 150 | 150 – 200 | 200 – 250 | 250 – 300 | 300 – 350 |
Frequency: | 2 | 3 | 5 | 6 | 5 | 3 | 1 |
Find the mode of the following distribution:
Class interval |
10 – 14 | 14 – 18 | 18 – 22 | 22 – 26 | 26 – 30 | 30 – 34 | 34 – 38 | 38 – 42 |
Frequency | 8 | 6 | 11 | 20 | 25 | 22 | 10 | 4 |
Mode is
If mode of a series exceeds its mean by 12, then mode exceeds the median by
For the following distribution
C.l. | 0 - 5 | 5 - 10 | 10 - 15 | 15 - 20 | 20 - 25 |
f | 10 | 15 | 12 | 20 | 9 |
the difference of the upper limit of the median class and the lower limit of the modal class is?