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प्रश्न
Consider the following frequency distribution:
| Class | 0 – 5 | 6 – 11 | 12 – 17 | 18 – 23 | 24 – 29 |
| Frequency | 13 | 10 | 15 | 8 | 11 |
The upper limit of the median class is:
पर्याय
17
17.5
18
18.5
उत्तर
17.5
Explanation:
According to the question,
Classes are not continuous,
Hence, we make the data continuous by subtracting 0.5 from lower limit and adding 0.5 to upper limit of each class.
| Class | Frequency | Cumulative Frequency |
| 0.5 – 5.5 | 13 | 13 |
| 6.5 – 11.5 | 10 | 23 |
| 11.5 – 17.5 | 15 | 38 |
| 17.5 – 23.5 | 8 | 46 |
| 23.5 – 29.5 | 11 | 57 |
According to the question,
`N/2 = 57/2 = 28.5`
28.5 lies in between the interval 11.5 – 17.5.
Therefore, the upper limit is 17.5
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