Advertisements
Advertisements
प्रश्न
The median of first 10 prime numbers is
पर्याय
11
12
13
14
उत्तर
First 10 prime numbers are 2, 3, 5, 7, 11, 13, 17, 19, 23, 29.
n = 10 (even)
Media`= ((n/2)^(th)"term" +(n/2 +1)^(th) "term")/2`
`=(5^(th) "term" +6^(th ) "term")/2`
`=(11 +13)/2`
`= 24/2`
`=12`
Hence, the correct option is (b).
APPEARS IN
संबंधित प्रश्न
100 surnames were randomly picked up from a local telephone directory and the frequency distribution of the number of letters in the English alphabets in the surnames was obtained as follows:
Number of letters | Number of surnames |
1 - 4 | 6 |
4 − 7 | 30 |
7 - 10 | 40 |
10 - 13 | 6 |
13 - 16 | 4 |
16 − 19 | 4 |
Determine the median number of letters in the surnames. Find the mean number of letters in the surnames? Also, find the modal size of the surnames.
Following is the distribution of I.Q. of loo students. Find the median I.Q.
I.Q.: | 55 - 64 | 65 - 74 | 75 - 84 | 85 - 94 | 95 - 104 | 105 - 114 | 115 - 124 | 125 - 134 | 135 - 144 |
No of Students: | 1 | 2 | 9 | 22 | 33 | 22 | 8 | 2 | 1 |
If the median of the following frequency distribution is 32.5, find the values of `f_1 and f_2`.
Class | 0 – 10 | 10 – 20 | 20 – 30 | 30 -40 | 40 – 50 | 50 – 60 | 60 – 70 | Total |
Frequency | `f_1` |
5 |
9 | 12 | `f_2` | 3 | 2 | 40 |
Find the correct answer from the alternatives given.
Distance Covered per litre (km) | 12 - 14 | 14 - 16 | 16 - 18 | 18 - 20 |
No. of cars | 11 | 12 | 20 | 7 |
The median of the distances covered per litre shown in the above data is in the group . . . . . .
The annual rainfall record of a city for 66 days is given in the following table :
Rainfall (in cm ): | 0-10 | 10-20 | 20-30 | 30-40 | 40-50 | 50-60 |
Number of days : | 22 | 10 | 8 | 15 | 5 | 6 |
Calculate the median rainfall using ogives of more than type and less than type.
Pocket expenses of a class in a college are shown in the following frequency distribution:
Pocket expenses |
0 - 200 |
200 - 400 |
400 - 600 |
600 - 800 |
800 - 1000 |
1000 - 1200 |
1200 - 1400 |
Number of students | 33 | 74 | 170 | 88 | 76 | 44 | 25 |
Then the median for the above data is?
Will the median class and modal class of grouped data always be different? Justify your answer.
Find the values of a and b, if the sum of all the frequencies is 120 and the median of the following data is 55.
Marks | 30 – 40 | 40 – 50 | 50 –60 | 60 – 70 | 70 –80 | 80 – 90 |
Frequency | a | 40 | 27 | b | 15 | 24 |
The median of the following frequency distribution is 35. Find the value of x.
Class: | 0 – 10 | 10 – 20 | 20 – 30 | 30 – 40 | 40 – 50 |
Frequency: | 6 | 3 | x | 12 | 19 |
A life insurance agent found the following data for distribution of ages of 100 policy holders. Calculate the median age, if policies are given only to persons having age 18 years onwards but less than 60 year.
Age (in years) | Number of policy holders |
Below 20 | 2 |
Below 25 | 6 |
Below 30 | 24 |
Below 35 | 45 |
Below 40 | 78 |
Below 45 | 89 |
Below 50 | 92 |
Below 55 | 98 |
Below 60 | 100 |