मराठी

If the Median of the Following Frequency Distribution is 32.5, Find Values of `F_1 and F_2`. Class 0 – 10 10 – 20 20 – 30 30 -40 40 – 50 50 – 60 60 – 70 Total Frequency `F_1` 5 9 12 `F_2` 3 2 40 - Mathematics

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प्रश्न

If the median of the following frequency distribution is 32.5, find the values of `f_1 and f_2`.

Class 0 – 10 10 – 20 20 – 30 30 -40 40 – 50 50 – 60 60 – 70 Total
Frequency `f_1`

 

5

9 12 `f_2` 3 2 40

 

उत्तर

Class Frequency (f) Cumulative Frequency (cf)
0 – 10 `f_1` `f_1`
10 – 20 5 `f_1`+5
20 – 30 9 `f_1`+14
30 – 40 12 `f_1`+26
40 – 50 `f_2` `f_1`+`f_2`+26
50 – 60 3 `f_1`+`f_2`+29
60 – 70 2 `f_1`+`f_2`+31
  N = Σ𝑓 = 40  

Now,` f_1 + f_2 + 31 = 40`
⇒` f_1 + f_2 = 9`
⇒ `f_2 = 9 - f_1`
The median is 32.5 which lies in 30 – 40.
Hence, median class = 30 – 40
Here, `l = 30, N/2 = 40/2 = 20, f = 12 and cf = 14 + f_1`
Now, median = 32.5
`⇒ l + ((N/2−Cf)/f) × h = 32.5`

`⇒ 30 + ((20 −(14 + f1))/ 12)× 10 = 32.5`
`⇒ (6 − f_1)/ 12` × 10 = 2.5
`⇒ (60 − 10f_1)/12 = 2.5`
`⇒ 60 – 10f_1 = 30`
`⇒ 10f_1 = 30`
`⇒ f_1 = 3`
From equation (i), we have:
`f_2 = 9 – 3`
`⇒ f_2 = 6`

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पाठ 9: Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive - Exercises 2

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आर एस अग्रवाल Mathematics [English] Class 10
पाठ 9 Mean, Median, Mode of Grouped Data, Cumulative Frequency Graph and Ogive
Exercises 2 | Q 10

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