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प्रश्न
Find the mode of the following distribution:
| Class interval |
10 – 14 | 14 – 18 | 18 – 22 | 22 – 26 | 26 – 30 | 30 – 34 | 34 – 38 | 38 – 42 |
| Frequency | 8 | 6 | 11 | 20 | 25 | 22 | 10 | 4 |
उत्तर
As the class 26 – 30 has the maximum frequency, it is the modal class.
Now,` x_k = 26, h = 4, f_k = 25, f_k-1 = 20, f_k+1 = 22`
∴ Mode,` M_0 = x_k + {ℎ ×((fk− fk−1))/((2fk− fk−1−fk+1))}`
=`26+{4xx ((25-20))/((2xx25-20-22))}`
=`26+{4xx5/8}`
= (26 + 2.5)
= 28.5
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