Advertisements
Advertisements
प्रश्न
Given below is the distribution of total household expenditure of 200 manual workers in a city:
Expenditure (in Rs) | 1000 – 1500 | 1500 – 2000 | 2000 – 2500 | 2500 – 3000 | 3000 – 3500 | 3500 – 4000 | 4000 – 4500 | 4500 – 5000 |
Number of manual workers |
24 | 40 | 31 | 28 | 32 | 23 | 17 | 5 |
Find the average expenditure done by maximum number of manual workers.
उत्तर
As the class 1500-2000 has the maximum frequency, it is the modal class.
Now, `x_k = 1500, h = 500, f_k = 40, f_k-1 = 24, f_k+1 = 31`
∴ Mode, `M_0 = x_k + {ℎ ×((f_k− f_k−1))/((2f_k− f_k−1−f_k+1))}`
=1500+ `{500 xx ((40-24))/((2 xx40-24-31))}`
=`1500+ {500xx 16/25}`
=(1500+320)
=1820
Hence, mode = Rs 1820
APPEARS IN
संबंधित प्रश्न
Compute the mode of the following data:
Class | 0 – 20 | 20 – 40 | 40 – 60 | 60 – 80 | 80 – 100 |
Frequency | 25 | 16 | 28 | 20 | 5 |
The agewise participation of students in the annual function of a school is shown in the following distribution.
Age (in years) | 5 - 7 | 7 - 9 | 9 - 11 | 11 – 13 | 13 – 15 | 15 – 17 | 17 – 19 |
Number of students | x | 15 | 18 | 30 | 50 | 48 | x |
Find the missing frequencies when the sum of frequencies is 181. Also find the mode of the data.
Find the mode of the following frequency distribution:
x | 10 | 11 | 12 | 13 | 14 | 15 |
f | 1 | 4 | 7 | 5 | 9 | 3 |
State the modal class.
Class Interval | 50 - 55 | 55 - 60 | 60 - 65 | 65 - 70 | 70 - 75 | 75 - 80 | 80 - 85 | 85 - 90 |
Frequency | 5 | 20 | 10 | 10 | 9 | 6 | 12 | 8 |
For the following distribution
Marks | No. of students |
Less than 20 | 4 |
Less than 40 | 12 |
Less than 60 | 25 |
Less than 80 | 56 |
Less than 100 | 74 |
Less than 120 | 80 |
the modal class is?
In the formula `x-a+(sumf_i d_i)/(sumf_i),` for finding the mean of grouped data d1's are deviations from the ______.
If xi's are the midpoints of the class intervals of grouped data, fi's are the corresponding frequencies and `barx` is the mean, then `sum(f_ix_i-barx)` is equal to ______.
For the following distribution
Monthly Expenditure (Rs.) | No. of families |
Expenditure less than Rs. 10,000 | 15 |
Expenditure les than Rs. 13,000 | 31 |
Expenditure les than Rs. 16,000 | 50 |
Expenditure les than Rs. 19,000 | 67 |
Expenditure les than Rs. 22,000 | 85 |
Expenditure les than Rs. 25,000 | 100 |
The number of families having expenditure range (in ?) 16,000 - 19,000 is?
Which of the following is not a measure of central tendency?
The monthly income of 100 families are given as below:
Income (in Rs) | Number of families |
0 – 5000 | 8 |
5000 – 10000 | 26 |
10000 – 15000 | 41 |
15000 – 20000 | 16 |
20000 – 25000 | 3 |
25000 – 30000 | 3 |
30000 – 35000 | 2 |
35000 – 40000 | 1 |
Calculate the modal income.