Advertisements
Advertisements
प्रश्न
A 220V, 50Hz ac source is connected to a coil having coefficient of self-induction of 1H and a resistance of 400 Ω. Calculate:
- the reactance of the coil.
- the impedance of the coil.
- the current flowing through the coil.
उत्तर
1. Reactance of coil, XL= `2pi f L`
= 2 × 3.14 × 50 × 1 Ω
= 314 Ω
2. Impedance of coil,
Z = `sqrt(R^2 + X_L^2)`
= `sqrt(400^2 + 314^2)`
= `sqrt(160000 + 98596)`
= `sqrt(258596)`
= 508.5 Ω
3. Current flowing in coil, `I =V/Z`
= `220/508.5 A`
= 0.43 A
APPEARS IN
संबंधित प्रश्न
Why is choke coil needed in the use of fluorescent tubes with ac mains?
An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series across a source of emf V = 10 sin 340 t. The power loss in AC circuit is
Define inductive reactance and give its units.
When does power factor of a series RLC circuit become maximum?
Why is choke coil needed in the use of fluorescent tubes with ac mains? Why can we not use an ordinary resistor instead of the choke coil?
In an alternating current circuit consisting of elements in series, the current increases on increasing the frequency of supply. Which of the following elements are likely to constitute the circuit?
- Only resistor.
- Resistor and an inductor.
- Resistor and a capacitor.
- Only a capacitor.
In young's double slit experiment `"d"/"D"`= 10-4 D (d = distance between slits, D = distance of screen from the slits). At a point P on the screen resulting intensity is equal to the intensity due to individual slit l0. Then the distance of point P from the central maximum is (λ = 6000 `"A"^°`)
A 50 Hz AC source of 20 volts is connected across R and C as shown in figure. The voltage across R is 12 volt. The voltage across c is ______.
A series CR circuit with R = 200 Ω and C = (50/π) µF is connected across an ac source of peak voltage ε0 = 100 V and frequency v = 50 Hz. Calculate (a) impedance of the circuit (Z), (b) phase angle (Φ), and (c) voltage across the resistor.
An alternating current I = 14 sin (100 πt) A passes through a series combination of a resistor of 30 Ω and an inductor of `(2/(5pi))` H. Taking `sqrt2` = 1.4 calculate the rms value of the voltage drops across the resistor and the inductor.
