Advertisements
Advertisements
प्रश्न
A , B and C are collinear points such that AB = `1/2` AC . If the coordinates of A, B and C are (-4 , -4) , (-2 , b) anf (a , 2),Find the values of a and b.
उत्तर
`"AB"/"AC" = 1/2`
∴ AB : BC = 1 : 1
Coordinates of B are ,
B (- 2 ,b) = B `((- 4 + "a")/2 , (-4 + 2)/2)`
`-2 = (-4 + "a")/2` , b = -1
- 4 = - 4 +a , b = -1
The values of a and b are 0 and -1 respectively.
APPEARS IN
संबंधित प्रश्न
Points A(–5, x), B(y, 7) and C(1, –3) are collinear (i.e. lie on the same straight line) such that AB = BC. Calculate the values of x and y.
Points P(a, −4), Q(−2, b) and R(0, 2) are collinear. If Q lies between P and R, such that PR = 2QR, calculate the values of a and b.
M is the mid-point of the line segment joining the points A(–3, 7) and B(9, –1). Find the coordinates of point M. Further, if R(2, 2) divides the line segment joining M and the origin in the ratio p : q, find the ratio p : q.
Find the centroid of a triangle whose vertices are (3, -5), (-7, 4) and ( 10, -2).
A triangle is formed by line segments joining the points (5, 1 ), (3, 4) and (1, 1). Find the coordinates of the centroid.
A lies on the x - axis amd B lies on the y -axis . The midpoint of the line segment AB is (4 , -3). Find the coordinates of A and B .
As shown in the figure. two concentric circles are given and line AB is the tangent to the smaller circle at T. Shown that T is the midpoint of Seg AB
The midpoint of the line segment joining (2a, 4) and (-2, 2b) is (1, 2a+1). Find the value of a and b.
show that the points A(- 1, 2), B(2, 5) and C(- 5, – 2) are collinear.
The points A(−5, 4), B(−1, −2) and C(5, 2) are the vertices of an isosceles right-angled triangle where the right angle is at B. Find the coordinates of D so that ABCD is a square
Find the coordinates of the mid-point of the line segment with points A(– 2, 4) and B(–6, –6) on both ends.