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प्रश्न
A. hot solid of mass 60 g at 100°C is placed in 150 g of water at 20° C. The final steady temperature recorded is 25°C. Calculate the specific heat capacity of the solid. [Specific heat capacity of water = 4200 J kg-1 °C-1]
उत्तर
Mass of hot solid m = 60 gm, at 100 C
Mass of water, m2 = 150 gm, at 20 C
Final temperature = 25 C
By principle of calorimetry,
Heat given = Heat taken
⇒ m1c1ΔQ1 = m2c2ΔQ2
⇒ 60 × c × (100 - 25) = 150 × 4.2 × (25 - 20)
⇒ ∴ Required specific heat, c1 = 0.7 J/ gm °C
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