Advertisements
Advertisements
प्रश्न
A path of 8 m width runs around the outsider of a circular park whose radius is 17 m. Find the area of the path.
उत्तर
The radius (r) of the inner circle is 17 m.
The radius (R) of the outer circle is 25 m. [Includes path, i.e (17 + 8)]
Area of the path `= pi"R"^2 - pi"r"^2`
`=pi("R"^2-"r"^2)`
`=22/7(25^2 - 17^2)`
`=22/7xx(25-17)(25+17)`
`=22/7xx8xx42`
= 1056 m2
∴ Area of the path = 1056 m2
APPEARS IN
संबंधित प्रश्न
A bicycle whell makes 5000 revolutions in moving 11 km. Find the diameter of the wheel
Find the diameter of the circle whose area is equal to the sum of the areas of two circles having radii 4 cm and 3 cm.
The circumference of a circle is 8 cm. Find the area of the sector whose central angle is 72°.
The circumference of a circle is equal to the sum of the circumference of two circles having diameters 36 cm and 20 cm. The radius of the new circle is
The diameter of a wheel is 84 cm. How many revolutions will it make to cover 792 m?
The radius of the circle is given below; find the area.
28 cm
Find the circumference of the circle whose area is 81π cm 2.
What is the circumference of a circle of diameter 10 cm (Take π = 3.14)?
Sudhanshu divides a circular disc of radius 7 cm in two equal parts. What is the perimeter of each semicircular shape disc? (Use π = `22/7`)
Find the radius of a circle whose circumference is equal to the sum of the circumferences of two circles of radii 15 cm and 18 cm.