Advertisements
Advertisements
प्रश्न
A piece of cloth cost Rs 5000. If the cost price of the cloth was Rs 5 less per meter, SOm more of the cloth would have been purchased. Find the cost price per meter of cloth and length of the cloth purchased.
उत्तर
Let the cloth meters purchase initially was a meters.
Then , Cost per meter = `5000/"a"`
New cost per meter = `5000/("a" - 5)` , which enabled to buy 50 meter more.
⇒ In new condition, (Cost per meter) x (total length)= total cost `(5000/"a" - 5)("a" + 50) = 5000`
⇒ (5000 - 5a) (a + 50)= 5000 a
⇒ 5000 a + 250000 - 5a2 - 250a = 5000a
⇒ 5a2 + 250 a - 250000 = 0
⇒ a2 + 50 a - 500000 = 0
⇒ a2 + 250 a - 200a - 500000 = 0
⇒ a (a + 250) - 200 (a + 250) = 0
⇒ (a + 250)(a - 200) = 0
⇒ a = 200 Meters .
⇒ Cost per meter = 5000/ 200 = Rs 25 / meter
Hence answer is Rs 25/ meter and 200 meters.
APPEARS IN
संबंधित प्रश्न
Solve : x² – 10x – 24 = 0
Determine whether x = -1 is a root of the equation x2 – 3x +2=0 or not.
Solve `(1200/x + 2)(x - 10) - 1200 = 60`
Solve the following equation using the formula:
`(x - 1)/(x - 2) + (x - 3)/(x - 4) = 3 1/3`
If -1 and 3 are the roots of x2+px+q=0
then find the values of p and q
Solve:
(x2 – 3x)2 – 16(x2 – 3x) – 36 = 0
Solve the following equation by using formula :
`(3x - 4)/(7) + (7)/(3x - 4) = (5)/(2), x ≠ (4)/(3)`
Solve the following equation by using formula :
x2 + (4 – 3a)x – 12a = 0
Choose the correct alternative answer for the following sub questions and write the correct alphabet.
Which of the following is not a quadratic equation?
A train travels a distance of 90 km at a constant speed. Had the speed been 15 km/h more, it would have taken 30 minutes less for the journey. Find the original speed of the train.