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प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
Frequency of the allele (A).
उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
Frequency of allele, p(A) = 1 − 0.4
= 0.6
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संबंधित प्रश्न
What does the following equation represent? Explain.
p2 + 2pq + q2 = 1
With the help of an algebraic equation, how did Hardy-Weinberg explain that in a given population the frequency of occurrence of alleles of a gene is supposed to remain the same through generations?
Differentiate between Directional natural selection and Disruptive natural selection.
How does the Hardy-Wienberg equation explain genetic equilibrium?
Very short answer question.
State the Hardy – Weinberg equilibrium.
A population will not exist in Hardly Weiberg equilibrium if ____________.
Disturbance of Hardy - Weinberg equilibrium results in
For the MN-blood group system, the frequencies of M and N alleles are 0.7 and 0.3, respectively. The expected frequency of MN-blood group bearing organisms is likely to be ______.
Name the law that states that the sum of allelic frequencies in a population remains constant. What are the five factors that influence these values?
List any two factors that can disturb the genetic equilibrium.
