Advertisements
Advertisements
प्रश्न
A population of 200 fruit flies is in Hardy Weinberg equilibrium. The frequency of the allele (a) 0.4. Calculate the following:
The number of homozygous dominant fruit flies.
उत्तर
In Hardy Weinberg, p2 + 2pq + q2 = 1, where 'p2' is the frequency of the homozygous dominant genotype (AA), '2pq' is the frequency of the heterozygous genotype (Aa), and 'q2' is the frequency of the homozygous recessive genotype (aa).
Given:
q = 0.4
We know p + q = 1
p = 1 − q
= 1 − 0.4
= 0.6
number of homozygous dominant fruit flies is As,
p2(AA) = (0.6)2
= 0.36
= 0.36 × 200
= 72
APPEARS IN
संबंधित प्रश्न
Differentiate between Directional natural selection and Disruptive natural selection.
According to the Hardy-Weinberg principle, the allele frequency of a population remains constant. How do you interpret the change of frequency of alleles in a population?
Multiple choice question.
In Hardy - Weinberg equation, the frequency of homozygous recessive individual is represented by:
How does Hardy-Weinberg’s expression (p2+2pq+q2=1) explain that genetic equilibrium is maintained in a population? List any four factors that can disturb the genetic equilibrium.
Explain how mutations, natural selection and genetic drift affect Hardy Weinberg equilibrium.
In a population, Hardy Weinberg equilibrium is disturbed by following factors EXCEPT ______.
The factor that leads to the Founder effect in a population is ______
State and explain any three factors affecting allele frequency in populations.
Gene flow occurs through generations. and can occur across language barriers in humans. If we have a technique of measuring specific allele frequencies in different population of the world, can we not predict human migratory patterns in pre-history and history? Do you agree or disagree? Provide explanation to your answer.
How is Hardy-Weinberg's expression “(p2 + 2pq + q2) = 1” derived?
